how to change logarithmic equations to exponential form .
\[\log x =5 \] \[\ln 1=0 \] \[\ln 300x=1\]
\[\Huge \log_a x = n\] \[\Huge \text{Becomes:}\] \[\Huge x = a^n\]
logs has a base of 10
\[\text{Since there is no base specified we assume \it has the base of 10.}\] \[\Huge \log_{10} x = 5\]
\[\text{Using the rule posted, what can you conclude?}\]
yes i can do it but how about ln ?!
Cancel the logarithm by taking exp of both sides.
\[\huge \ln ~300x = 1\] \[\huge e*\ln~300x = 1*e\] \[\huge 300x = e\] \[\huge x = \frac{ e }{ 300 }\] e and ln are inverses of each other and cancel out :)
ok ,i see how ?thanks alot \[\log x =5 \] become \[10^5=x\]
\[\large \ln~1 = 0~~~ \checkmark ~~\text{this is true so you can leave \it as that i guess}\]
Yep, you got it.
so i don't have to change \[\ln1=0 \]
Nope, the logarithm of one is zero.
You can plug it into your calculator and you'll see that it is true if you want. ln 1 = 0
what if i did e it will be like this \[e.\ln1=0 .e\] \[1=0.e\] but it is false \[1=0\]
You aren't solving for a variable -.-
The logarithm of 1 is zero.
you would only multiply by e to both sides when you are solving for a variable.. in this case the ONLY thing you do is punch ln 1 into your calculator, and you'll get the value which is 0.
ok ,get but i have to be change can i say like this
\[loge 1=0 \]
LN1=0, if you raise both sides to e, it will be e^(LN1)=e^(0), 1=1 which means there are infinite number of solutions
They just want you to change logarithmic equations to exponential form. 1) x = 10^5 2) 1 = e^0 3) 300x = e^1 = e
yes i know but i am asking if i can do it like this \[\ln 1=0\] \[loge 1=0\] \[e^0=1\] \[1=1\]
I would stop at e^0 = 1 because you have now changed it from logarithmic equation to an exponential equation.
Ok ,so it right yeah ?!
1) x = 10^5 2) 1 = e^0 3) 300x = e^1
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