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how find the derivative of f(x)=sin(x)^x ?!
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\[ f(x)=\sin(x)^x \]
\[x \epsilon (0,\pi)\]
start by taking log on both sides log f(x) =.....
Please ln both sides
you should get lnf(x)=xln(sinx)
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y= sinx^x as hartnn said take log for both log y= x log x nw deff both side for x , then but insted of y ,sinx ^x
f(x)=e^(xln(sinx))
use e's derivative and you should get an answer for dy/dx
is the answer is like this @shakesworde
YES, thats correct that can also be simplified one step further, if required.
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how ?! to simplify @hartnn ?!
for one thing, cos x/ sin x = cot x but the 1st term, e^(xln sin x ) can be simplified using the fact that e^ln A = A as sin x^x
i see, thanks @ hartnn
welcome ^_^
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