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Physics 8 Online
OpenStudy (anonymous):

A particle moves along the X-axis as x=u(t-2s)+a(t-2s)^2 (a) the initial velocity is u (b) the acceleration is a (c) the acceleration is 2a (d) at t=2s the particle is at the origin

OpenStudy (theeric):

Hi! Is there a question here?

OpenStudy (anonymous):

yeahh ...do u know it ..?

OpenStudy (vincent-lyon.fr):

Your particle is simply undergoing a uniformly accelerated linear motion. Obviously (d) is a correct statement. The initial velocity is u-4a The acceleration is 2a At t=2s, the particle is at the origin.

OpenStudy (chenping):

Substituing t=2s into your equation... u get x = 0 ! :)

OpenStudy (anonymous):

yes thank you very much ..!

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