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A particle moves along the X-axis as x=u(t-2s)+a(t-2s)^2 (a) the initial velocity is u (b) the acceleration is a (c) the acceleration is 2a (d) at t=2s the particle is at the origin
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Hi! Is there a question here?
yeahh ...do u know it ..?
Your particle is simply undergoing a uniformly accelerated linear motion. Obviously (d) is a correct statement. The initial velocity is u-4a The acceleration is 2a At t=2s, the particle is at the origin.
Substituing t=2s into your equation... u get x = 0 ! :)
yes thank you very much ..!
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