Given triangle ABC with A(-3,4) B(5,8) and C(2,-2) , write the equation of the line containing mid segment XZ in standard form , Where x is the midpoint of AB and Z is the midpoint of BC ?
@nikato I made a new question so it didn't get so crowded . can you help me with this one ?
@Kokirian
@someoneelse
do u have graph paper?
No.
|dw:1388124183812:dw|ill try my best then
okay now what ? I have NO clue how to do this .
|dw:1388124311008:dw|
6x+5y=36 6x-5y=24 i can't decide between them two ? @nirmalnema
mid points are..(1,6) and (7/2,3) now by using two point formula you will get the equation of line (y-y1)=m(x-x1) m = (y2-y1)/(x2-x1) = -6/5 (y-6)=-6/5(x-1) 5(y-6)=-6(x-1) 5y-30=-6x-6 6x+5y-36 is required equation
sorry by mistake i deleted the previous solutions
Which of the following when placed in standard position , lands in quadrant 4 ? , 256 -280 -5 135
@nirmalnema do you know how to figure out that one ?
in the 4 quadrant.... x is positive and y is negative so what are these points of y axis or x axis.. can you plz give both the co ordinates together ..
@nirmalnema they didn't give me both the coordinates together.
@Akpellet_math do you know it ?
so we cant say with any one co ordinate.. but still there are chances of -280 and -5 being in 4 quadrant
yeahh ...the above efforts are correct ..:))
it depends on there relative x co ordinates
@nirmalnema which one should I put ?
sorry it cant be determined..without knowing x co ordinates..
can you try to help me with one more before I just try to turn this test in ?
yup sure... i will
you will get the coordinates of X and Z as (1,6) and (3.5,3) respectively. then you must apply the 2 point form of straight lines to get the equation ...\[\frac{ y-y1 }{ y1-y2 } =\frac{ x-x1 }{ x1-x2 }\]
ABC has vertices A(0,0) B(3,3) C(6,0). Write the equation of the line containing the altitude AR in standard form .
this is a different question right .?? the previous answer is 4x+5y-34=0
@Akpellet_math yes
|dw:1388126010507:dw|ur diagram
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