Question

Given that f(x) = x2 + 3x + 6 and g(x) = the quantity of x plus two, over three, solve for f(g(x)) when x = 1.

Answer 1

have you tried it yet?

Answer 2

No, I dont even know where to start.

Answer 3

what is equation of g(x) ?

Answer 4

x-3/2

Answer 5

(x plus 2) over (3)\[\frac{x+2}{3}\]

Answer 6

am i right?

Answer 7

yeah

Answer 8

we want to evaluate f(g(x)) when x=1

Answer 9

plug in g(x) for every x in f(x) and solve

Answer 10

so let's find the equation of f(g(x))

Answer 11

plugging g(x) in f(x) \[f(g(x))=(g(x))^2+3g(x)+6\]and we have the formula for g(x) so\[f(g(x))=\left( \frac{x+2}{3} \right)^2+3\frac{x+2}{3}+6\]

Answer 12

am i clear? makes sense?

Answer 13

yeah i think im getting it

Answer 14

very good, can you evaluate f(g(1)) ?

Answer 15

oh jeez...haha okay. so is the answer 11

Answer 16

10 or 11? :-)

Answer 17

check it once more :-)

Answer 18

10

Answer 19

good

Answer 20

oh i got it!! thank you so much!!!

Answer 21

Welcome :-)