3(a - 3) = 2(a + 4)
using the distributive property of multiplication on the left side gives\[3(a-3)=3a-3\cdot 3\] I suggest you use the distributive property on both sides, then gather all terms with the variable on one side, and all constants on the other
i need help because i dont understand, please explain
if you have something on the outside of the brackets, you are multiplying everything on the inside by what's on the outside. the distributive property basically says that you can multiply each term on the inside by what's on the outside, like this:\[3\times(a+b+c)=3a+3b+3c\]does that make sense so far?
yes
right on. So if we distribute on both sides of the equation\[3(a-3)=2(a+4)\]\[3a-3\cdot 3=2a+2\cdot4\]
well im on online school and only have 19 minutes left on this test and this is my last question.
so to solve for a, we should then gather like terms. In other words, all the terms that have "a" in them should be brought to one side, and those without "a" to the other
well I'm not going to give you the answer, but I'm helping you work through it right?
Yes , so 3a-3 and 2a+4
we had 3a-3*3 on the left; what's 3 times 3?
9
and similarly on the right we had 2a+4*2 so don't forget to multiply the 4 by 2 as well which gives us\[3a-9=2a+8\]
ok
how would we get the a's together on one side of the equation?
add 3+2 to get 5a?
we need to do the same thing to both sides of the equation. look at just the right side\[2a+8\]if we want to get rid of 2a on that side, we subtract 2a so it would cancel\[2a+8-2a\]but we need to do the same thing to both sides, so subtract 2a from the left side as well
\[3a-9-2a=2a+8-2a\]how does that end up if you combine like terms?
you um
will have ... Geez man i dont know, im in seventh grade and they have me taking eight grade math for some reason
well let's look at the left first\[3a-9-2a=a-9\]since 3a-2a=1a=a
Ok . i think i see
can you do the right on your own?\[2a+8-2a=?\]hint: 2a-2a=0
so the right is 8?
exactly. then we have\[a-9=8\]
what do we do to both sides of the equation to get a by itself?
youre really gonna think im dumb, but subtract 8 from 9?
9-8=1 so we would still have a 1 on the left
subtract 9 from 8 for negative 1?
if we add 9 to -9, what do we get?
0
which is what we want, since a+0=a then a would be by itself on the left. so let's add 9 to both sides
ok
\[a-9+9=8+9\]
\[a-18=17\] ?
you did the right side right, but look at the left\[a-9+9=a+0=a\]
im confused
let me write it like this\[a-9=8\]\[a-9+9=8+9\]\[a+0=17\]\[a=17\]
ohhhhhhhhhh! the answer is 17.
yep
thanks bro, ill be sure to make sure i ask you when i need math help
my pleasure; good luck on your test.
thanks , i got a 80
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