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Mathematics 22 Online
OpenStudy (anonymous):

3(a - 3) = 2(a + 4)

OpenStudy (anonymous):

using the distributive property of multiplication on the left side gives\[3(a-3)=3a-3\cdot 3\] I suggest you use the distributive property on both sides, then gather all terms with the variable on one side, and all constants on the other

OpenStudy (anonymous):

i need help because i dont understand, please explain

OpenStudy (anonymous):

if you have something on the outside of the brackets, you are multiplying everything on the inside by what's on the outside. the distributive property basically says that you can multiply each term on the inside by what's on the outside, like this:\[3\times(a+b+c)=3a+3b+3c\]does that make sense so far?

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

right on. So if we distribute on both sides of the equation\[3(a-3)=2(a+4)\]\[3a-3\cdot 3=2a+2\cdot4\]

OpenStudy (anonymous):

well im on online school and only have 19 minutes left on this test and this is my last question.

OpenStudy (anonymous):

so to solve for a, we should then gather like terms. In other words, all the terms that have "a" in them should be brought to one side, and those without "a" to the other

OpenStudy (anonymous):

well I'm not going to give you the answer, but I'm helping you work through it right?

OpenStudy (anonymous):

Yes , so 3a-3 and 2a+4

OpenStudy (anonymous):

we had 3a-3*3 on the left; what's 3 times 3?

OpenStudy (anonymous):

9

OpenStudy (anonymous):

and similarly on the right we had 2a+4*2 so don't forget to multiply the 4 by 2 as well which gives us\[3a-9=2a+8\]

OpenStudy (anonymous):

ok

OpenStudy (anonymous):

how would we get the a's together on one side of the equation?

OpenStudy (anonymous):

add 3+2 to get 5a?

OpenStudy (anonymous):

we need to do the same thing to both sides of the equation. look at just the right side\[2a+8\]if we want to get rid of 2a on that side, we subtract 2a so it would cancel\[2a+8-2a\]but we need to do the same thing to both sides, so subtract 2a from the left side as well

OpenStudy (anonymous):

\[3a-9-2a=2a+8-2a\]how does that end up if you combine like terms?

OpenStudy (anonymous):

you um

OpenStudy (anonymous):

will have ... Geez man i dont know, im in seventh grade and they have me taking eight grade math for some reason

OpenStudy (anonymous):

well let's look at the left first\[3a-9-2a=a-9\]since 3a-2a=1a=a

OpenStudy (anonymous):

Ok . i think i see

OpenStudy (anonymous):

can you do the right on your own?\[2a+8-2a=?\]hint: 2a-2a=0

OpenStudy (anonymous):

so the right is 8?

OpenStudy (anonymous):

exactly. then we have\[a-9=8\]

OpenStudy (anonymous):

what do we do to both sides of the equation to get a by itself?

OpenStudy (anonymous):

youre really gonna think im dumb, but subtract 8 from 9?

OpenStudy (anonymous):

9-8=1 so we would still have a 1 on the left

OpenStudy (anonymous):

subtract 9 from 8 for negative 1?

OpenStudy (anonymous):

if we add 9 to -9, what do we get?

OpenStudy (anonymous):

0

OpenStudy (anonymous):

which is what we want, since a+0=a then a would be by itself on the left. so let's add 9 to both sides

OpenStudy (anonymous):

ok

OpenStudy (anonymous):

\[a-9+9=8+9\]

OpenStudy (anonymous):

\[a-18=17\] ?

OpenStudy (anonymous):

you did the right side right, but look at the left\[a-9+9=a+0=a\]

OpenStudy (anonymous):

im confused

OpenStudy (anonymous):

let me write it like this\[a-9=8\]\[a-9+9=8+9\]\[a+0=17\]\[a=17\]

OpenStudy (anonymous):

ohhhhhhhhhh! the answer is 17.

OpenStudy (anonymous):

yep

OpenStudy (anonymous):

thanks bro, ill be sure to make sure i ask you when i need math help

OpenStudy (anonymous):

my pleasure; good luck on your test.

OpenStudy (anonymous):

thanks , i got a 80

OpenStudy (anonymous):

Do you play video games like Call of duty , or anything?

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