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MEDAL GIVEN TO CORRECT ANSWER. A student measured the density of gold to be 19.1 g/cm3. The accepted value of the density of gold is 19.3 g/cm3. What is the percent error of the student's measurement? A. 1.04% B. 1.39% C. 0.20% D. 1.71%
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First calculate the absolute error.. then convert it into percentage .. simple ^_^.. can u try?!
I think the percent error should be calculated like this: |Approximate Value - Exact Value|/|Exact Value| *100%
I don't get c using this method.
I got A. is that correct? @nincompoop @joannablackwelder
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Yup! That's what I get.
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