OpenStudy (anonymous):

MEDAL GIVEN TO CORRECT ANSWER. A student measured the density of gold to be 19.1 g/cm3. The accepted value of the density of gold is 19.3 g/cm3. What is the percent error of the student's measurement? A. 1.04% B. 1.39% C. 0.20% D. 1.71%

3 years ago
OpenStudy (anonymous):

First calculate the absolute error.. then convert it into percentage .. simple ^_^.. can u try?!

3 years ago
OpenStudy (joannablackwelder):

I think the percent error should be calculated like this: |Approximate Value - Exact Value|/|Exact Value| *100%

3 years ago
OpenStudy (joannablackwelder):

I don't get c using this method.

3 years ago
OpenStudy (anonymous):

I got A. is that correct? @nincompoop @joannablackwelder

3 years ago
OpenStudy (joannablackwelder):

Yup! That's what I get.

3 years ago