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Mathematics 16 Online
OpenStudy (anonymous):

Which equation could be solved using the graph above? A. x^2+4x+3=0 B. x^2-4x+3=0 C. x^2-6x+9=0 D. x^2-1=0

OpenStudy (anonymous):

@Agent47

OpenStudy (sleepyjess):

Can you screen shot the graph? You have to sign in to get to the link you posted.

OpenStudy (anonymous):

how do you screen shot it

OpenStudy (sleepyjess):

Are you on a mac or pc?

OpenStudy (anonymous):

pc

OpenStudy (sleepyjess):

Go to Snipping Tool

OpenStudy (anonymous):

And where is that?

OpenStudy (sleepyjess):

Go to Start, Programs... look there or possibly utitlities

OpenStudy (phi):

I would look at your graph and find what is its y value when x is 0 ?

OpenStudy (phi):

I would also look for its x value at the vertex (where it "bottoms out")

OpenStudy (anonymous):

OpenStudy (anonymous):

@sleepyjess

OpenStudy (amoodarya):

roots are x=-1,-3 vertex (-2,-5) (x-(-1))(x-(-3))

OpenStudy (anonymous):

ok

OpenStudy (amoodarya):

hint : when all the roots are negative ---->all the coefficient are positive (or all negative)

OpenStudy (phi):

amood has the best way to do this. You could multiply out (x+1)(x+3) and see which answer matches that

OpenStudy (anonymous):

ok but im having trouble understanding

OpenStudy (phi):

First, can you multiply out (x+1)(x+3) ?

OpenStudy (anonymous):

no you guys are telling me different things I struggle with math and just need someone to tell me how to do this in the easiest way possible

OpenStudy (anonymous):

@Agent47 What do you think

OpenStudy (agent47):

They're both right, only using different approaches. I find phi's approach easier. You know the two x interceptions: (-3, 0) and (-1, 0) So when x=-3, y=0; and when x=-1, y=0.

OpenStudy (agent47):

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