Question

Medals and fan-ing

Answer 1

A system of equations is given below.
2x + 7y = 1
-3x – 4y = 5

A.) Create an equivalent system of equations by replacing the first equation by multiplying the first equation by an integer other than 1, and adding it to the second equation.
B.) Use any method to solve the equivalent system of equations (the new first equation with the original second equation).
C.) Prove that the solution for the equivalent system is the same as the solution for the original system of equations.

Answer 2

@Trojan

Answer 3

I think I've got this one for you :-)
I'm doing it by multiplying the first equation by 2

Answer 4

Ok

Answer 5

@sleepyjess where did you go??

Answer 6

4x+14y=2
−6x−8y=10

Since 14y does not contain the variable to solve for, move it to the right-hand side of the equation by subtracting 14y from both sides.

4x=−14y+2
−6x−8y=10

Reorder the polynomial −14y+2 alphabetically from left to right, starting with the highest order term.

4x=2−14y
−6x−8y=10

Divide each term in the equation by 4.
\[\frac{ 4x }{ 4 }=\frac{ 2 }{ 4 }-\frac{ 14y }{ 4 }\]−6x−8y=10

Cancel the common factor of 4
x=\[\frac{ 4x }{ 4 }=\frac{ 2 }{ 4 }-\frac{ 14y }{ 4 }\]-6x−8y=10

Cancel the common factor of 2
x=\[\frac{ 1}{ 2 }-\frac{ 7y }{ 2 }\]-6x−8y=10

Answer 7

I just wanted to let you know, I haven't gotten to polynomials yet

Answer 8

Replace all occurrences of x with the solution found by solving the last equation for x.
\[x=\frac{ 1 }{ 2 }-\frac{ 7y }{ 2 }\]\[-6(\frac{ 1 }{ 2 }-\frac{ 7y }{ 2 })-8y=10\]
Multiply −6 by each term inside the parentheses
\[x=\frac{ 1 }{ 2 }-\frac{ 7y }{ 2 }\]\[-6(\frac{ 1 }{ 2 })-6(\frac{ -7y }{ 2 })-8y=10\]
Multiply −6 by the 1/2 inside the parentheses.

Answer 9

If you haven't gotten to polynomials yet, is this going to help then?

Answer 10

Yes I still understand but you said something about polynomials so I thought I would say something

Answer 11

Ok... I'll continue then :-)

Answer 12

Is that all or is there more?

Answer 13

@sleepyjess

Answer 14

Put the rest in the attachment

Answer 15

A lot faster ... lol

Answer 16

It won't show up :(

Answer 17

Do you have Word?

Answer 18

Yea, that's what I use

Answer 19

It should open it up in word for you.