Initially, Greg had a total of 60 records and cassettes in his music collection. He then sold 1/8 of his cassettes and 1/2 of his records. If the number of records he sold is twice the number of cassettes he sold, how many records did he sell?
@satellite73

Question

Initially, Greg had a total of 60 records and cassettes in his music collection. He then sold 1/8 of his cassettes and 1/2 of his records. If the number of records he sold is twice the number of cassettes he sold, how many records did he sell?
@satellite73

anonymous · Answer

i hate word problems

calculusxy · Answer

Me too.

anonymous · Answer

we need a variable, lets say $x$ is the number of records, so $60-x$ is the number of cassettes

anonymous · Answer

the number of records sold is $\frac{1}{2}x$ and the number of cassettes sold is $\frac{1}{8}(60-x)$

anonymous · Answer

since the number of records sold is twice the number of cassettes sold, we know 
$$\frac{2}{8}(60-x)=\frac{1}{2}x$$ and we can solve for $x$
by which i think i mean " you can solve for $x$
i would multiply both sides by 4 first

calculusxy · Answer

Would that be 120/8 - 2/8x=1/2x?

calculusxy · Answer

@mathstudent55

anonymous · Answer

multiply by 4 first and start with 
$$60-x=2x$$ then it will be easy

anonymous · Answer

$$\frac{2}{8}(60-x)=\frac{1}{2}x\
\frac{1}{4}(60-x)=\frac{1}{2}x\
4\times \frac{1}{4}(60-x)=4\times \frac{1}{2}x\
60-x=2x$$ etc

anonymous · Answer

when was this question written, 1976??