Question

Please help :)
Find the points of intersection of the graphs of y = x^2 and y=3x-2

Answer 1

equate the 2 equations and solve

\[x^2 = 3x -2\]

or

\[x^2 - 3x + 2 = 0\]

you'll need 2 points of intesection. So solve for x then substitute them into either equation to find the corresponding y values

Answer 2

points of intersection are when both graphs go through the same point.
This means both X and Y in both functions are equal to each other.

since Y of the first function and Y of the second function are equal, then set both equations equal to each other and solve it.

x^2 = 3x -2

then move it over

x^2 -3x + 2 = 0

and factor

(x-2)(x-1) = 0

or x = 2 and x = 1

Answer 3

thanks guys :) @campbell_st @polaris_s0i