Two forces with magnitudes of 100 and 50 pounds act on an object at angles of 50° and 160° respectively. Find the direction and magnitude of the resultant force. Round to two decimal places in all intermediate steps and in your final answer. (I have this so far) u = 100 (cos 50), (sin 50) = (64.28),(76.60) v = 50 (cos 160), (sin 160) = (-46.98),(17.10) w = u + v w = (64.28 + -46.98), (76.60 + 17.10) w = (15.30),(93.70) w = √((15.3)^2+(93.7)^2) w = 94.94 magnitude tan^-1 (93.7/15.3)
theres none
yep i think you're correct
@kc_kennylau i just dont know the direction part
@melacho but you worked it out... tan^-1(93.7/15.3)
Wait is that it or do i have to solve that
|dw:1388377677288:dw|
you need to get out a calculator and calculate its value
so just plug that in the calculator? . tan^-1(93.7/15.3)
exactly
|dw:1388377949243:dw|
I;m getting something close to 80
that's good
would it be in the 1st quadratnt?
exactly
so my answer for direction is 80 in the 1st qudrant?
it's just asking you about the (a)direction and the (b)magnitude...
so what should i put?
Thank you by the way! :)
the direction is "something near 80", and the magnitude you've calculated it: "w = 94.94 magnitude"
THANK YOU SO MUCH!
no problem :DDDDDDDDDDDDDDDDDDD
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