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Mathematics 21 Online
OpenStudy (anonymous):

Two forces with magnitudes of 100 and 50 pounds act on an object at angles of 50° and 160° respectively. Find the direction and magnitude of the resultant force. Round to two decimal places in all intermediate steps and in your final answer. (I have this so far) u = 100 (cos 50), (sin 50) = (64.28),(76.60) v = 50 (cos 160), (sin 160) = (-46.98),(17.10) w = u + v w = (64.28 + -46.98), (76.60 + 17.10) w = (15.30),(93.70) w = √((15.3)^2+(93.7)^2) w = 94.94 magnitude tan^-1 (93.7/15.3)

OpenStudy (anonymous):

theres none

OpenStudy (kc_kennylau):

yep i think you're correct

OpenStudy (anonymous):

@kc_kennylau i just dont know the direction part

OpenStudy (kc_kennylau):

@melacho but you worked it out... tan^-1(93.7/15.3)

OpenStudy (anonymous):

Wait is that it or do i have to solve that

OpenStudy (kc_kennylau):

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OpenStudy (kc_kennylau):

you need to get out a calculator and calculate its value

OpenStudy (anonymous):

so just plug that in the calculator? . tan^-1(93.7/15.3)

OpenStudy (kc_kennylau):

exactly

OpenStudy (kc_kennylau):

|dw:1388377949243:dw|

OpenStudy (anonymous):

I;m getting something close to 80

OpenStudy (kc_kennylau):

that's good

OpenStudy (anonymous):

would it be in the 1st quadratnt?

OpenStudy (kc_kennylau):

exactly

OpenStudy (anonymous):

so my answer for direction is 80 in the 1st qudrant?

OpenStudy (kc_kennylau):

it's just asking you about the (a)direction and the (b)magnitude...

OpenStudy (anonymous):

so what should i put?

OpenStudy (anonymous):

Thank you by the way! :)

OpenStudy (kc_kennylau):

the direction is "something near 80", and the magnitude you've calculated it: "w = 94.94 magnitude"

OpenStudy (anonymous):

THANK YOU SO MUCH!

OpenStudy (kc_kennylau):

no problem :DDDDDDDDDDDDDDDDDDD

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