Question

What kind of transformation results from multiplying the pre-image's matrix of coordinates by a scalar of 9 ?

A. The image is translated 9 units to the right of the pre-image.
B. The image is rotated clockwise 9° from the pre-image.
C. The image is dilated to nine times the size of the pre-image.
D. The image is shrunk until it is 1/9 the size of the pre-image.

Answer 1

have you tried with something simple? so you get an idea...

Answer 2

you there?

Answer 3

No, I didn't see any clear lesson in my lesson, it didnt tell me anything about this.

Answer 4

Take a couple of points and multiply the coordinates by 9. for example, (1,1) is a point. if you multiply the scalar 9, you get the new point (9, 9).

if you have a point (1/9, -1) -> (1, -9)

etc.

now think about a shape... let's start with a line segment.

say from (0, 0) to (1, 0). if we multiply by the scalar 9, we get (0, 0) to (9, 0).

the length of the first segment is 1 and the length of the last is 9. Any segment will also grow by a factor of 9. this will also apply to any shape.

saw we have a line segment from (1, 1) to (2, 2). after multipling the coordinates by the scalar 9, we get the new points (9, 9) to (18, 18) the length is again multiplied by 9.

the original length was \(\sqrt2\) and the new length is \(9\sqrt2\). check and you'll see.