27^1001 is divided by 13. is there any short cut for this kind of problems
u sure u got the exponent number right? the result comes out to be too huge, i might add even as infinity
What is the remainder when 27^1001 is divided by 13, and the remainder when 38^101 is divided by 13? How would I then show that 70 x 27^1001 + 38^101 is divisible by 13?
another question : What is the remainder when 17^23 is divided by 16? how to solve this kind of problems? need a short cut
What is the remainder when 27^1001 is divided by 13 let me ask u a question : whats remainder when 27 is divided by 13 ?
1
yes, 27 = 1 (mod 13) (27)^anything = 1^anything (mod 13)
mod is just a fancy way of saying remainder
70 x 27^1001 + 38^101 (mod 13) is same as 70 x 1^1001 + 38^101 (mod 13)
work 38^101 also similar way whats the remainder when 38 is divided by 13 ?
12
thats right, but we can also represent remainder in negatives right ?
remainder of 12 means, 12 is extra remainder of -1 means, 1 is missing
both 12 and -1 mean same, when talking about remainder ok ?
hope you can do the rest :)
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