What transformation has changed the parent function f(x) = log2 x to its new appearance shown in the graph below? @rm152
@ranga
we need pictures lol
sorry i forgot @inkyvoyd
@rm152
It has been shifted upwards 3 units.
f(x + 2) + 3 like that
Compare it to how \[\Large y = \log_{2} x\]would look like and you will see what shifts have taken place. The function has been shifted both along the x-axis and the y-axis. If you compare the graph you will know the amount by which it has been shifted along each axis and you can come up with the function.
I have a feeling it is also compressed or stretched. What are the options.
f(x + 3) + 2 f(x − 3) − 2 f(x + 2) + 3 f(x − 2) − 3
what do you think @ranga @rm152
The first answer f(x+3) + 2
The function y = log(x) has a vertical asymptote at x = 0. This function has a vertical asymptote at x = -2. Therefore, the function has been shifted to the left by 2 units. Shifting to the left by 2 units is same as replacing x by (x + 2). \[\Large y = \log_{2} (x+2) + k\] When x = 0, the log function is 1. The y-intercept on the graph is 4. So k must be 3. Therefore, \[\Large y = \log_{2} (x+2) + 3\] or y = f(x+2) + 3
theres a part b to the question which is equivalent to \[\log_{125}25 \] 1.076 3 / 2 2 / 3 2/5
Let \[\log_{125}25 = \log_{5}25 / \log_{5}(125)= ?\]
2/3
Yes.
woohooo!
Alright.
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