Question

How do i solve
-3e^(2X)+16=5?
Help pleaseeeeee

Answer 1

-3e^(2X)+16=5
-3e^(2X)=5-16
-3e^(2X)=-11
e^(2X)=11/3
now get log( base e ) from both sides

Answer 2

\[-3e ^{2x}=-11 \rightarrow e ^{2x}=\frac{ 11 }{ 3 }\rightarrow 2x=\ln(\frac{ 11 }{ 3 })\]

Answer 3

Thanks both of you!

Answer 4

thank you

Answer 5

rm

Answer 6

NP