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Find the point on the terminal side of θ = negative three pi divided by four that has an x coordinate of -1? I know the answer is (-1,-1), but I don't know how.
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Yea, you could of it many ways. But use a triangle.
A triangle?
this is an equilateral triangle, so the y value is the same as the x value not equilateral, "isosceles" angles are π4,π2,π4 so two legs are equal
and welcome 2 os
Yup, we know \[\LARGE \theta=-\frac{3\pi}{4}\] |dw:1388425000609:dw| Since we know that the one side is -1, we just need to find x. Also, anything that's a radian with 4 in it is 45 degrees, and a 45 degree triangle: |dw:1388425146933:dw| So they would be the same. Plus only tan/cot is positive in the third quad.
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