Question

If you attach a 50.0 g mass to the spring whose data are shown in the graph, what will be the period of its oscillations? (attachment)

Answer 1

From the graph, we have its slope is 0.04 which is k in F = -kx of the spring
So, k = 0.04
and \(\omega =\sqrt{\dfrac{k}{m}}=\sqrt{\dfrac{0.04}{0.05}}=0.89\)
Then period T = \(\dfrac{\omega}{2\pi}=\dfrac{0.89}{2*3.1417}=0.1416\)

Answer 2

but it sounds like Physics than Maths

Answer 3

No one is ever on physics.. :/ I'm really desperate. I reallllllyy appreciate you helping and explaining. :) You are a life saver. Medal for you!! <3

Answer 4

ty

Answer 5

pi =3.14159265... = 3.1417 ????

Answer 6

Else, fine. Just keeping you on your toes.

Answer 7

@douglaswinslowcooper Thanks for pointing it out. OMG I used pi =3.1417 during my physics course and believed that was correct.