Question

Please can you check the attachment ?

Answer 1

@myininaya

Answer 2

You can use young's modulus.

\[Y=\frac{ F*L _{0} }{ A _{0}*\Delta L } \]

where;

Y is young's modulus constant
F is force
Lo is initial length
Ao is initial cross section
Delta L is change on length

Answer 3

@oksuz_ well i thought of this method to reach up to my answer, but i have no clue on how exactly to use it in order to find the answer

Answer 4

@myininaya

Answer 5

@oksuz_ is right
you need to use this equation
you can modify it
you can write it in this form
\[Fl/AY = \Delta l \]
so for the first rod,
F=F
l=l
A=pi(d^2 / 4)
and we can assume the young's modulus to be any thing
say Y
so the young's modulus for all the rods will be Y
as all are made up of the same material
so for the rod A, the change in length(delta l)=4Fl/pi d^2 Y
similarly you can find it for the other rods and you'll get it maximum for rod A
hope this helps you:)

Answer 6

Ok, so the formula of the extension is given by the equation:
\[\Delta L=\frac{ L_0F }{ AY}\]
What is then the extension of wire A?

Answer 7

hello,
@Fifciol
the extention in wire A is\[4F l \div \pi d ^{2} Y\]

Answer 8

@rajat97 I asked @Lama97

Answer 9

oh! i'm sorry

Answer 10

@rajat97 im wondering why did u divide the diameter with 4 ?

@Fifciol i believe the extension for wire A is