Question

@AdrDiazEs
Indicate in standard form the equation of the line through the given points.

K(6, 4), L(-6, 4)

What formula do I use?

Answer 1

@helpme1.2

Answer 2

this is what a standard form looks like, \[\huge ax+by = c\]

Answer 3

first find the slope of a line. do you know how to find the slope ?

Answer 4

ermm, I probably have before but I dont remember. /.\

Answer 5

wait wait lemme check

Answer 6

\[\frac{ y2-y1 }{ x2-x1 }\] ?

Answer 7

yes, you're on the right track, now plug the points and solve to find the slope

Answer 8

I think I messed up lol... I got \[\frac{ 4 - 4 }{ -6 - 6 }\]

Answer 9

which is 0/-12

Answer 10

yes and \[\frac{ 0 }{ -12 } = 0 \] so the slope would be 0

Answer 11

now you have the slope, use a tangent line formula of \[\huge y-y_1 = m(x-x_1)\] m is the slope and plug in the points

Answer 12

\[\huge (6,4) = (\color {red}{x_1, y_1 })\]

Answer 13

( 6 , 4 ) = (6,4) ?

Answer 14

i meant to say, you can use those points and plug them into the tangents line formula

Answer 15

ooohhh lol. y-4=0(x-6) ?

Answer 16

now distribute the \[\huge 0(\color{green}{x-6}) \]

Answer 17

the zero to x-6

Answer 18

so you would have \[\huge y-4 = 0\]

Answer 19

now try to put that in to the standard form that i gave you at the beginning

Answer 20

x + y - 4 + 0 ?

Answer 21

in this case the