Oneee more lol Find the coordinates of the midpoint of the segment whose endpoints are (10, 6) and (-4, 8). @Yttrium
I'm horrible at remembering the formulas because I just started this advanced school and didnt learn any of this before so I'm just kinda stuck! Lol.
It's easy. Just get the averages of coordinates at x and y and that's it. :)
at a time, practice few problems which use same formula! you'll remember that formula for long time :)
In short, add them and just divide by two. Separate from x and y and you will form the coordinates of it's midpoint.
yeah, an if you want the equation of the formula, The co-ordinates of midpoint(x,y) on the line segment with end-points (x1,y1) and (x2,y2) is just the average of co-ordinates, given by : \(\large x=\frac{x_1+x_2}{2}\) \(\large y=\frac{y_1+y_2}{2}\) now,just put the values and find the co-ordinates of midpoint (x,y).
So basically \[\frac{ x1 + x2 }{ 2 } and \frac{ x1+y1 }{ 2 }\]
?
Yup @CrayolaCrayon_
Ahh I thought so!
(y1+y2)/2 *** but i think you meant that only
Oh yes, that is what I meant!
so what mid-point you got for (10, 6) and (-4, 8). ??
so it's \[\frac{ 10+6 }{ 2 } and \frac{ -4+8 }{ 2 }\] ?
nopes, what u did is you added x and y co-ordinates you needed to add x co-ordinates of both points
x1 = 10 x2 = -4 x= ... ?
Oh oops wait!
\[\frac{ 10-4}{ 2} and \frac{ 6+8 }{ }\]
oops, forgot the 2 lol
yes, and those = ... ? simplify
\[\frac{ 16 }{ 2 } and \frac{ 14 }{ 2 } \rightarrow \frac{ 8 }{ 1 } and \frac{ 7 }{ 1 } \rightarrow\] 8 and 7
where does 16 come from ? 10-4 = ... ?
oopsss! I'm so tired I can't think straight lol. I accidentally added. Make that 3 and 7 haha
(3,7)
you are \(\huge \color{red}{\checkmark}\)
thank you!
welcome ^_^
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