Question

a*.25 + (1-a)*.5 + 2* a * (1-a) *.25 *.5 *-.25

Answer 1

What are we going to do here?

Answer 2

set equal to 0 and solve for a

Answer 3

Hmmm. Maybe I can show you it's simplified form and then you try to solve it. :)
Here it is
\[.25a+ .5(1-a) + 2*.25*.5a(1-a)-.25 = 0\]
\[.25a+.5-.5a+.25a-.25a^2-.25 = 0\]
Hence
\[-.25a^2+.25 = 0\]
Then you continue :p

Answer 4

@perdue , do you get it?

Answer 5

i was away for a second
i'm going to try it now, thanks for simplifying it :)

Answer 6

I'm getting that a = 1 but I know that a is supposed to = ,75

Answer 7

Oopss. My answer is also 1 tho. Where did you get .75?

Answer 8

i have the answer from the professor

Answer 9

Maybe try to check your given again. I think there's something wrong with it. :)

Answer 10

k thank you I'll take a look at it

Answer 11

a*.25 + (1-a)*.5 + 2* a * (1-a) *.25 *.5 *(-.25) =0

Answer 12

I'm getting something close to the .75 (.732), there could be some issues with rounding

Answer 13

Is it something like this?

Answer 14

.5 -.1875 -.0625a^2=0 is what I'm getting

Answer 15

when you simplify the right side of the equation you get .0625

Answer 16

multiplied by (a - a^2)

Answer 17

.5 - .25a + .0625a -.0625a^2 =0

Answer 18

I think it is a rounding error
when you combine like terms and add the 'a coefficient terms' to both sides you get
.5 = .1875a + .0625a^2

Answer 19

isn't it be .25a+.5-.5a+.0625a-.0625a^2 = 0 ??

Answer 20

yes that is right let me check it again, my algebra sucks

Answer 21

but when you combine like terms -
.25a -.5a + .0625a = (-.1875)

Answer 22

so
.5 -.1875a - .0625a^2 = 0

Answer 23

How did you get your answer, did you used quadratic formula? Sorry huh, i do not have calculator here.

Answer 24

actually I'm still not sure on the answer
I'll let you know if/when I figure this out

Answer 25

I have here the quadratic formula. Maybe this could help you.
The quadratic equation in the form of ax^2 + bx + c = 0 may solve the roots thru this formula.
\[x = \frac{ -b \pm \sqrt{b^2 - 4ac} }{ 2a }\]
where
a = -.0625a^2
b = -.1875a
and c = .5
Just substitute the values over this formula

Answer 26

thank you :)

Answer 27

I hope it will lead to .75 haha lol