Evaluate the integral ∫(x2 + 4x -2)dx from x = 1 to x = 4.
A. 16 B. 25 C.45 D. 49
Integrate it first
what does that mean?
You don't know what integrate means? ._.
......no. im not good at this stuff
\( \int x^n dn = \dfrac{x^{n + 1}}{n+1} + C \)
It means work backwards to the original equation. But looks like mathstudent is cooking something up, so I'll wait~
Integration is the opposite of differentiation. If you start with a function and you integrate it you get a new function. If you differentiate the new function, you get your original function back.
so i just plug everything in?
and if so, what is n?
For example: \( \int (x^2 + 3x + 1)dx = \dfrac{x^3}{3} + \dfrac{3x^2}{2} + x + C\) Now differentiate the new function: \( \dfrac{d}{dx} (\dfrac{x^3}{3} + \dfrac{3x^2}{2} + x + C) \) = \(= \dfrac{3x^2}{3} + \dfrac{6x}{2} + 1\) \(= x^2 + 3x + 1\) As you can see, when you integrate and differentiate, you get back to the same starting point.
Follow the integration part of my example.
how did u get 3 and 2 as denominators?
Look at the formula for integrating x^n: \(\int x^n dn = \dfrac{x^{n + 1}}{n+1} + C\)
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