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Find the Taylor series generated by f(x)=sin^2x at x=π /2 edit: I thought that we should be using π /2 as "a" in taylor series formula. but in the answer π /2 is positive.
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First off, this should make sense that the answer is positive, since the square of a negative or positive number is always positive. So what are you doing here? Are you taking the derivative of sin^2(x) and at each derivative evaluating it at π/2?
Before you even do that, it might help to rewrite \(\sin^2x=\dfrac{1}{2}-\dfrac{1}{2}\cos2x\) to avoid all that product/power rule.
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