Solve by the linear combination method (with or without multiplication).
2x + 8y = –2
5x + 6y = 9
A.
(3, –1)
B.
(–2, 2)
C.
(–2, 7)
D.
(–1, 3)
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OpenStudy (anonymous):
@DSS
OpenStudy (anonymous):
@robtobey @Compassionate @campbell_st
OpenStudy (anonymous):
lil help
OpenStudy (anonymous):
You can use elimination. To do this you must get one variable to cancel out. Try this:
2x + 8y = –2 -5(2x+8y=-2) -10x-40y=10
5x + 6y = 9 2(5x+6y=9) 10x + 12y = 18
-28y = 28
y = -1
You now have y...substitute -1 into the equations to get x.
2x+8(-1)=-2 5x+6(-1)=9
2x - 8 = -2 5x-6=9
2x=6 5x=15
x=3 x=3 It works in both equations so (3,-1)
OpenStudy (anonymous):
@DSS thx
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