Question

Solve log(2x + 1) = 3

Answer 1

Transform your equation with a log into the equation with an exponent.
Use the definition of log below.

\( \log_b x = y \iff b^y = x\)

Answer 2

first, set 3 = log 1000
log (2x + 1) = 3
log (2x + 1) = log 1000

now take an equation :
2x + 1 = 1000
solve for x

Answer 3

\[\log{(2x+1)}=3\]
Use: \[\log_b x = y \iff b^y = x\]
\[10^3 = (2x + 1)\]
\[1000 = 2x +1\]
\[999 = 2x\]
\[999\div 2=199.5\]
\[x=199.5\]