how do you find the 5th root of 32 and the cube roots of 3√3 + 3i
wold you start out with z=32 z=32cis0 z^(1/5) cis(2pi k /5) for the first one?
*would
*32^(1/5) in front of the cis
Are you familiar with the polar form of a complex number?
yep
OK, that will help you to solve these questions. First find the polar form of 32
6cis pi/6?
Sorry I am not sure what you mean by cis
6(cospi/6+ i sin pi/6)
isn' that what you meant by polar?
No, that is called the Euler form
Some people call your notation the polar form. I learnt it differently, sorry. Check this video, it is exactly what you need http://www.youtube.com/watch?v=VOFyDPBTT5w
thanks
another video from MIT that agrees with my studies :) http://www.youtube.com/watch?v=sn3orkHWqUQ
You can learn a lot from youtube
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