Algebra 2 help?!?!?! The height h in feet of a baseball on Earth after t seconds can be modeled by the function h(t) = -16(t - 1.5)2 + 36, where -16 is a constant in ft/s2 due to Earth's gravity. The gravity on Mars is only 0.38 times that on Earth. If the same baseball were thrown on Mars, it would reach a maximum height 59 feet higher and 2.5 seconds later than on Earth. Write a height function for the baseball thrown on Mars. Help? Now sure how to adjust the equasion...
Would it be just making it -16t^2+24+30=0 turned into y = -6.08(t - 4)2 + 95 by multiplying by 0.38?
looks good
I would do the problem by noticing the vertex on earth is (1.5,36) the vertex on mars will be (1.5+2.5, 36+59) or (4,95) the -16 coefficient on earth gets changed to -16*0.38= -6.08 so in vertex form, plugging in the numbers for (h,k) and a in y= a(x-h)^2 + k y= -6.08(t-4)^2 + 95
ok, great so I did it right? so will my way of just multiplying each thing by 0.38 work all the time or was this just a fluke?
good question.
the earth's equation comes from physics, and starts with earth's force due to gravity... so your trick probably works for this situation. But if the equation were some random parabola, I don't think it works. I think they expect you to solve it the way I did.
Oh, ok I'll copy and paste your comment to a word where I can use it as an example then! THANKS!! AGAIN!!!
can you explain what you did in more detail ?
I took the original equasion (h(t) = -16(t - 1.5)^2 + 36) and multiplied each section by 0.38 (h(t) = -16x0.38 (t - 1.5x0.38)^2 + 36 to get y = -6.08(t - 4)^2 + 95 as the only option that had both of the first two right, not sure how I got from 36 to 95, my notes are beyond sloppy but I did it some how...
ok, in that case, the only thing you should multiply by 0.38 is the -16. you "tweak" the 1.5 and the 36 by adding the numbers they told you.
oh ok so 2.5 s longer and 59 ft higher gets added there?
yes
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