help When rolling a number cube, what is the probability of rolling a number greater than 2?
A.. 2/3 b. 5/6 c. 1/4 D. 1/2
you can either get a 1 2 3 4 5 or 6 which of those numbers are higher than 2?
3 up
list them out...
I think its C going by what inkyvoyd said
one last one pleasee?
You know @Monster143 , I never finished talking, and I can assure you that I don't believe the answer is C.
While I appreciate your attempt to help, I am trying to guide @NakaliNovatek to the answer instead of merely presenting it to him.
I'm srry...please forgive me...I should've just let you do it...
im a she to let you knwo
@NakaliNovatek , sorry for getting that wrong. Could you please list out the possibilities for rolls higher than 2?
umm not exaclty sure im osrry im really stressed out right now
so out of 1,2,3,4,5, and 6, which numbers would be considered higher than 2?
3 4 5 6
ect ect ect
im sorry okay ill try
Yeah, so you have 3,4,5,6. Each of those have the same probability of being rolled, right?
right.
Do you know what the probability of getting any single number on the die would be?
or number cube, I guess.
either a 4 or 3
am i right?
No, I'm asking about the probability. for the probability you take the 1/total number of outcomes. Because you have 6 faces on a cube the probability of getting any number (1,2,3,4,5, or 6) is the same - 1/6
Does that make sense?
ohh okay thats makes more sence
but how would that be like the answe chpoises
i put 1 fourth i dont know if thats it
Well, you have to note that you can get a 3, 4, 5 OR a 6. The rule for probability is that if you want to get one event AND another event to happen, you multiply the two (if one event is unrelated to another). However, we have OR. In the case of an "OR" probability you simply add up all the non-intersecting probabilities. What I mean by non-intersecting is that each event must have nothing to do with the other. If you get a 3 on your die roll, does that have anything to do with getting a 4 on a die roll?
umm no
So the events are "independent" of each other entirely right?
umm i didnt get that
Here, let me try another way. look at the pie chart and tell me how much of it is occupied by 3,4,5 and 6|dw:1388700493026:dw|
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