Question

Find the equation of the tangent line to the curve f(x) = -2x^2 – 1 at x = 1.

Answer 1

take the derivative first.

Answer 2

uhm you should be able to do this problem by now

Answer 3

in calculus, in what order do you learn limits and derivatives?
I have calc 1 this coming semester, what can I do to prepare?

Answer 4

limits first, then derivatives.

Answer 5

limits and continuity, then derivatives, then differentiation, graph behavior and derivative applications

Answer 6

so logic follows that learning the tangent and secant of a line comes after derivatives?

Answer 7

what she is asking is part of applications of derivatives

Answer 8

that should be trig/ precalc

Answer 9

no not the same

Answer 10

first you learn the rules, then move on to applying them in concepts and stuff.

Answer 11

anyways, take the first derivative of your equation

Answer 12

what do you get?

Answer 13

:) so anyways I start with the derivative, f(x) = 2x^2 - 1 f'(x) = 4x

Answer 14

is it f(x) = -2x^2 -1 or f(x) = 2x^2 - 1?

Answer 15

- oops I wrote it wrong therefore it would be f'(x) = -4x

Answer 16

yes

Answer 17

you have the slope of the equation tangent to your original equation now.

Answer 18

it says at x = 1.
so f'(x) = 4x
f'(1) = 4

Answer 19

-4

Answer 20

no need for that previous comment, (my bad again..) it's just f'(x) = 4x
since its asking for the equation tangent line its just the first derivative.