Question

Limit question.

Answer 1

\[\lim_{x \rightarrow 9}\frac{ x-9 }{ \sqrt{x} -3}\]

Answer 2

factor the numerator

Answer 3

First you can see that it will equal 0, so you have to do a different rule.

Answer 4

conjugate

Answer 5

nvm

Answer 6

\[\frac{x-9}{\sqrt{x}-3}=\frac{(\sqrt{x}+3)(\sqrt{x}-3)}{\sqrt{x}-3}\] cancel replace \(x\) by \(9\)

Answer 7

Multiply both the top and bottom by sqrt(x) +3

This will give you (x-9)(sqrtx - 3)/x-9

Answer 8

You can cancel out (x-9) from both the top and bottom

Leaving you with (sqrt(x) - 3)

Does that make sense?

Answer 9

yeah that works as well
either way