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Mathematics 18 Online
OpenStudy (anonymous):

help

OpenStudy (anonymous):

umm on what?

OpenStudy (anonymous):

OpenStudy (anonymous):

the subject is my life ....

OpenStudy (anonymous):

lol

OpenStudy (anonymous):

if t, then c because that is the smallest circle

OpenStudy (anonymous):

since \(t\) is contained in \(c\) the statement "if \(t\) then \(c\)" is correct this just means if you are in \(t\) then you must also be in \(c\)

OpenStudy (anonymous):

if c then t

OpenStudy (anonymous):

no the other way around

OpenStudy (anonymous):

if you are in the small one, then you are in the big one if \(t\) then \(c\)

OpenStudy (anonymous):

oh lol i though its if u have the big circle u have the small one too

OpenStudy (anonymous):

@UsArmy3947

OpenStudy (anonymous):

oh no think of it physically

OpenStudy (usarmy3947):

sorry idk :(

OpenStudy (anonymous):

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OpenStudy (anonymous):

it is not "if you have the circle" it is "if you are in the small circle, then you must also be in the big one' but if you are in the big one it doesn't mean you have to be in the small one

OpenStudy (anonymous):

|dw:1388720029134:dw|

OpenStudy (anonymous):

thx

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