equation of a line perpendicular to y=-1/3x+1?. passing through the point (2,7)

Question

anonymous · Answer

The linear relationship between two perpendicular lines is that $m_1 = -\frac 1 m$. In other words, the second slope will be the negative multiplicative inverse of the first one.

anonymous · Answer

Gah. $m_1 = -\frac 1 m$.

anonymous · Answer

Thus, the slope is 3. Now, we have to find $b$.
$$y = mx + b \
y = 3x + b
7 = 3(2) + b
7 = 6 + b
b = 1$$
Thus, the equation is $y = 3x + 1$.

anonymous · Answer

Sorry for the bad formatting. I'm trying to get adapted to not using math.stackexchange.com.

anonymous · Answer

No problem! But if the given solutions are 

        A.    3x - y = -1
        B.    -3x + y = -1
        C.    3x - y = 1
        D.    -3x - y = 1
Then would the answer be B, or C? Or maybe something else entirely? @bloopman

anonymous · Answer

Ah, well, now we have to put it in standard form.
$$y = 3x + 1 \
-3x + y = 1$$
The answer is therefore B.

anonymous · Answer

Note all I did was subtract $3x$ from the right side.