Question

Three consecutive integers that have a sum of 48

Answer 1

Ooh that is a tricky problem. I will just have to think about it logically.
What is 48/3?

It is 16

Answer 2

Knowing that, I know that I will need a sum that will equal 16(3)

Well isn't 15+16+17 = 48

The 15 and 17 displace each other to make two 16

Does that make sense?

Answer 3

hi :)

Answer 4

if the middle number is \(n\), then the first number is \(n-1\) and the last number is \(n+1\). if you add \((n-1)+n+(n+1)\) you get \(3n\), so to find the middle number we merely solve:$$3n=48\\n=48/3=16$$

i.e. our middle number is \(16\). what are the first and last numbers?

Answer 5

15 an 17 is the answer?

Answer 6

the three numbers are 15, 16, and 17 -- yes!