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Mathematics 21 Online
OpenStudy (anonymous):

Marcie wants to enclose her yard with a fence. Her yard is in the shape of a triangle attached to a rectangle. See the figure below. Yard is shapred like a square and a triangle. The area of this figure can be found by the formula A = (wh) + 0.5(bh). If Marcie wants the total area to be larger than a specified value, she can use the formula A > (wh)+ 0.5(bh). Rewrite this formula to solve for b. Show all steps in your work.

OpenStudy (anonymous):

can someone plz help

OpenStudy (anonymous):

It is just asking for you to solve for b in the equation A > (wh)+ 0.5(bh). You do no have to solve for b buy just do the work as if you were trying to solve b. Do you understand?

OpenStudy (anonymous):

Are you there?

OpenStudy (anonymous):

To get you started, subtract (wh) from both sides of A > (wh)+ 0.5(bh). Like below A > (wh)+ 0.5(bh) A -(wh) > (wh) + -(wh)+ 0.5(bh) After doing the problem above, we get.. A - (wh) > 0.5(bh) Can you finish?

OpenStudy (anonymous):

I am here sorry

OpenStudy (anonymous):

do I divedboth sides by wh

OpenStudy (anonymous):

No, now you need to get b by its self. If you needed to get x by its self in 2x = 2 how would you?

OpenStudy (anonymous):

im sorry to sound like im stupid but for some reason I am struggling with this so if you can explain it alitte more in depth thank you

OpenStudy (anonymous):

u there

OpenStudy (anonymous):

do I add wh to both sides of the >

OpenStudy (anonymous):

The who concept of equations is to keep it balanced. What ever you do to one side of the equal side you have to do to the other side of the equal sign. If I subtract something from one side, I have to do it to the other side of the equal sign. If I divide from one side of the equal sign, I have to do the same to the other side of the equal sign. If I have the equation 2x + 4 = 6 I first have to get all my constants on one side of the equation and get my variable x alone To do that we use a few rules of algebra. We are going to use the addition property and the division property. In order to get things on one side of the equal sign and to remove it from the other side we use the addition property. In order to separate variables that are being multiplied to gather we use the division property. So 2x + 4 = 6 First we use the addition property 2x + 4 + (-4) = 6 + (-4) 2x + 0 = 2 2x = 2 Now 2x is like saying 2 times x so this means it is multiplication so we need to use division to get our x alone and by its self so we divide 2 on each side 2x/ 2 = 2/2 x = 1 Now we are done So the equation A > (wh)+ 0.5(bh) we want to solve for b First we need to use the addition property A > (wh)+ 0.5(bh) A - (wh) > (wh) + (-(wh))0.5(bh) A - (wh) > 0.5(bh) Now we need to use division to get b by its self. How would that look?

OpenStudy (anonymous):

i divide both sides by wh

OpenStudy (anonymous):

No you are trying to get b by its self

OpenStudy (anonymous):

wh has nothing to do with b so why divide it?

OpenStudy (anonymous):

ok then 0.5

OpenStudy (anonymous):

If you were trying to get w by its self then you would divide h

OpenStudy (anonymous):

Yes 0.5 but what else?

OpenStudy (anonymous):

the bh

OpenStudy (anonymous):

No, you want b left on one side of the equal sign.

OpenStudy (anonymous):

You would divid 0.5h which will leave b all by its self on one side of the equal sign

OpenStudy (anonymous):

ok i see

OpenStudy (anonymous):

So to solve for b would look like this A - (wh) > 0.5(bh) A - (wh) / 0.5h > 0.5(bh) / 0.5h A - (wh) / 0.5h > b or b < A -(wh) / 0.5h

OpenStudy (anonymous):

thank you for all your help

OpenStudy (anonymous):

\[ b < \frac{A - (wh)}{0.5h} \]

OpenStudy (anonymous):

You are welcome

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