2. (15 points) A recessive mutant allele, black, causes a very dark body in Drosophila when homozygous. The normal wild-type color is gray.

a. A black female is crossed to a heterozygous gray male. What are the parental genotypes?

b. What F1 phenotypic and genotypic ratios are produced from this cross? (Show your Punnett Square)

Question

2.	(15 points) A recessive mutant allele, black, causes a very dark body in Drosophila when homozygous.  The normal wild-type color is gray.  

a.	A black female is crossed to a heterozygous gray male. What are the parental genotypes?

b. What F1 phenotypic and genotypic ratios are produced from this cross? (Show your Punnett Square)

wolfe8 · Answer

Hello and welcome to OpenStudy. Give me a moment while I look for the same question I just helped with earlier.

wolfe8 · Answer

Here you go :) Enjoy your stay http://openstudy.com/users/wolfe8#/updates/52c5ca30e4b0fef2cba0a9ed

anonymous · Answer

thank you!

wolfe8 · Answer

You're very welcome. Good luck and enjoy your stay.

anonymous · Answer

$\frak\huge{Welcome~ to~ Openstudy!}$
a. Let the mutant allele be $b$-the mother has both. Parental genotypes are the letters (alleles) you assign to the black female and heterozygous gray male. Heterozygous means that this person has a mutant allele and a normal allele. Let the normal allele be $B$.
b. |dw:1388892158207:dw|
This is how you draw a punnet square cross.