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Chemistry 18 Online
OpenStudy (anonymous):

what is the molecular weight (molar mass) of gas with a density of 4.72 g/l at 124 celsius and 426 torr?

OpenStudy (anonymous):

@wolfe8

OpenStudy (anonymous):

the choices are 316 g/mol 274 g/mol 282 g/mol 85.7 g/mol

OpenStudy (anonymous):

i got 282 idk how

OpenStudy (wolfe8):

Well, you will have to use the formula PV=nRT. But you will have to convert the pressure to atm and temperature to Kelvin, and use R for Kelvin. Rearrange that so have every info you have on one side and what's left on the other side. Does that make sense?

OpenStudy (anonymous):

a little so would i plug in 0.560526316 atm into p? and 397.15 into t?

OpenStudy (wolfe8):

Yes. And what is the equation you have? (after rearranging as I said)

OpenStudy (anonymous):

0.56atmmmmm*397.15=what would be the n and r though im not sure?

OpenStudy (wolfe8):

We don't know n but R is 0.082

OpenStudy (anonymous):

oh so the equation would be 0.56atmmmmm*v=n*0.082*397.15kelvin

OpenStudy (wolfe8):

So please rearrange it to have all the unknowns on the left side.

OpenStudy (anonymous):

v/n=0.56atm*0.082*397.15kelvin is this right?

OpenStudy (wolfe8):

You can simplify that more haha. But now if you notice, what you have is volume over n. You are given mass over volume(density). How can you obtain mass over n? Hint: cancelling out.

OpenStudy (anonymous):

hang on im writing this down

OpenStudy (anonymous):

i was watching a youtube video earlier and it said that the r is 8.314 im confused

OpenStudy (wolfe8):

Well the R depends on what units you use for the others. If you notice, for 8.314 the unit is J/mol*K whereas what I have been showing is for when you use pressure instead of energy.

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