Ask your own question, for FREE!
Mathematics 20 Online
OpenStudy (anonymous):

Given the sequence in the table below, determine the sigma notation of the sum for term 4 through term 15. n an 1 5 2 −10 3 20

OpenStudy (anonymous):

@math&ing001

OpenStudy (math&ing001):

\[\sum_{n=4}^{15}(-1)^{n-1}2a _{n-1}\] with a1=5

OpenStudy (math&ing001):

Is that what you're looking for ?

OpenStudy (anonymous):

\[\sum_{n=4}^{15}5(-2)^{n+1}\]

OpenStudy (anonymous):

this is the option most close to yours

OpenStudy (math&ing001):

Let me check

OpenStudy (anonymous):

ok til then i'll write the other options for you

OpenStudy (math&ing001):

\[\sum_{n=4}^{15}5(-2)^{n-1}\] Does this figure in your choices ?

OpenStudy (anonymous):

\[\sum_{n=1}^{15}5(-2)^{n-2} \] \[\sum_{n=1}^{15}5(-2n)\] \[\sum_{n=1}^{15}5(-2n)^{n+1}\]

OpenStudy (anonymous):

these are the rest of the options

OpenStudy (math&ing001):

Look at my answer above.

OpenStudy (math&ing001):

Cause from the sequence given it should be n-1 not n+1

OpenStudy (anonymous):

so its the one i typed firrst

OpenStudy (math&ing001):

Yeah, except 2 should be at the power of n-1

OpenStudy (math&ing001):

I mean (-2)^(n-1)

OpenStudy (anonymous):

ok so its the one n=4? sorry I know I'm annoying

OpenStudy (math&ing001):

yes :)

OpenStudy (anonymous):

Thank You!!

OpenStudy (math&ing001):

Welcome !

OpenStudy (anonymous):

FLVS students:

OpenStudy (math&ing001):

Actually, Malice it's the first choice : \(\sum_{n=4}^{n=15} 5(-2)^{n-1} \)

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!