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Mathematics 23 Online
OpenStudy (anonymous):

Evaluate

OpenStudy (anonymous):

\[\sum_{n=3}^{12}20(0.5)^{n-1}\]

OpenStudy (anonymous):

Geometric

OpenStudy (anonymous):

You want to find the sum of the first 3 terms?

OpenStudy (anonymous):

no the sum of all 13 numbers

OpenStudy (anonymous):

Did you get an answer of 40

OpenStudy (anonymous):

I might be wrong

OpenStudy (math&ing001):

\[20\sum_{n=2}^{12}(\frac{ 1 }{ 2 })^{n-1}=20\frac{ 1-(\frac{ 1 }{ 2 })^{11} }{ 1-0.5 }\] That's the sum of a geometric series. I think you can do the rest !

OpenStudy (anonymous):

Yes I can but if i give a number i get can you tell me if its right or wrong?

OpenStudy (anonymous):

-39.980

OpenStudy (anonymous):

?

OpenStudy (math&ing001):

Should be 40. No negative sign

OpenStudy (anonymous):

You'll get 40 if you round it up

OpenStudy (anonymous):

9.99 19.95 29.98 39.96 these are the options

OpenStudy (anonymous):

The last one

OpenStudy (math&ing001):

@Chad123 is correct

OpenStudy (anonymous):

thank you both of you guys! chad can you give math&ing a medal and ill give you one

OpenStudy (anonymous):

I actually did thanks guys

OpenStudy (anonymous):

Math ing can you pls come to my new question?

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