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\[\sum_{n=3}^{12}20(0.5)^{n-1}\]
Geometric
You want to find the sum of the first 3 terms?
no the sum of all 13 numbers
Did you get an answer of 40
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I might be wrong
\[20\sum_{n=2}^{12}(\frac{ 1 }{ 2 })^{n-1}=20\frac{ 1-(\frac{ 1 }{ 2 })^{11} }{ 1-0.5 }\] That's the sum of a geometric series. I think you can do the rest !
Yes I can but if i give a number i get can you tell me if its right or wrong?
-39.980
?
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Should be 40. No negative sign
You'll get 40 if you round it up
9.99 19.95 29.98 39.96 these are the options
The last one
@Chad123 is correct
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thank you both of you guys! chad can you give math&ing a medal and ill give you one
I actually did thanks guys
Math ing can you pls come to my new question?
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