2(t+1)/3=2(t-1)/3
how did you getthat
Is this the equation? \( \dfrac{2(t+1)}{3}=\dfrac{2(t-1)}{3}\)
No solutions. Coefficient of t on both sides equal.
Nooo
Yes @mathstudent55
I Don't get it
Notice that both sides have a factor of 2/3, so multiply both sides of 3/2 to get rid of the 2/3.
I agree...no solution
\(\dfrac{\cancel{3}}{\cancel{2}} \cdot \dfrac{\cancel{2}(t+1)}{\cancel{3}}=\dfrac{\cancel{3}}{\cancel{2}} \cdot \dfrac{\cancel{2}(t-1)}{\cancel{3}}\) \(t + 1 = t - 1\)
What is the slope that passes through the pionts (-7.1) and (7.8) ?
Once you are this point, subtract t from both sides. \(t + 1 = t - 1\) \(1 =-1\) Since you have an equation that is false, that means there is no solution to this equation.
The slope of the line through points \( (x_1, ~y_1) \) and \((x_2, ~y_2) \) is given by \(m = \dfrac{y_2 - y_1}{x_2 - x_1} \)
Subtract the y values and write in the numerator. Subtract the x values and write it in the denominator. That is the slope.
Thnks
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