Red-green colorblindness is an X-linked recessive mutation. A colorblind female is crossed with a normal male.a. What are the parental genotypes? (Hint: the sex of the parent is important)

b. Diagram the F1 results from this cross. (Show your Punnett Square).

c. Diagram the F2 results. (Show your Punnett Square).

Question

Red-green colorblindness is an X-linked recessive mutation.   A colorblind female is crossed with a normal male.a.	What are the parental genotypes? (Hint: the sex of the parent is important)


b.	Diagram the F1 results from this cross.  (Show your Punnett Square).


c.	Diagram the F2 results. (Show your Punnett Square).

anonymous · Answer

If colorblindness is an x-linked recessive disorder and a female is affected with it, what genotype would she have do you know @MariaA8686?

anonymous · Answer

ccx?

anonymous · Answer

How would you basically write sex linked disorders in terms of a female genotype?

anonymous · Answer

What are the female chromosomes in the 23rd pair?

anonymous · Answer

I would write the punnet square  it as XC  and Xc  for females and the Male would be Xc and  Y

anonymous · Answer

Usually C is dominant c is recessive.

anonymous · Answer

so would it be Xc and Xc for  the female?

anonymous · Answer

Yes that's right. What would be the male?

anonymous · Answer

xC yC?

anonymous · Answer

The y chromosome is too small to carry any alleles, only the x can. So a male can either have colorblindness or no colorblindness- the cannot be carriers.

anonymous · Answer

so just XcY?

anonymous · Answer

Yes :) understand how to write genotypes now?

anonymous · Answer

Now you have to cross both genotypes in a punnet square.

anonymous · Answer

yes =) i like that point how the Y chromosome is too small to hold any alleles

anonymous · Answer

ok i will draw one..

anonymous · Answer

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