Question

Solve (x+8)(2x-1)>_ 0 show all working

Answer 1

the zeros are fairly clear,
\[x+8=0\iff x=-8\] and
\[2x-1=0\iff x=\frac{1}{2}\]

Answer 2

since
\[y=(x+8)(2x-1)\] is a parabola that opens up, it is negative between the zeros and positive outside them

Answer 3

you want to know where it is greater than or equal to zero
that will be two intervals, \(x\leq -8\) or \(x\geq \frac{1}{2}\) which you can write that way, or in interval notation as
\[(-\infty, -8]\cup [\frac{1}{2},\infty)\]