Question

Does anybody know how to solve this?

Answer 1

well identify the equation of each line.. since both lines are solid the inequality is

greater than or equal to or less than or equal to...

one line has a y intercept of -2 and the other has an intercept of 3

find the slope of each line...

then you'll be on the way to the answer

Answer 2

wait, the y-intercept is always going to be on the y-axis, right?

Answer 3

yes

Answer 4

something intercepted, or something arrived to, or something to come in contact with

if you intercept the runner on 1st base towards 2nd base, you TOUCH or CONTACT him, thus you intercept him

y-intercept, when the graph TOUCHES the y-axis

Answer 5

ok, and then, how do u find the slope?

Answer 6

The slope is the m, in y = mx + b

Answer 7

wait, in this certain problem, how would we know what m and b are?

Answer 8

Moving from point to point, slope can be determined by how far up and how far over you move...rise over run

Answer 9

Find "solid" points...ones that are clearlly directly on an intersection

Answer 10

oh, so we can find any points?

Answer 11

yes

Answer 12

(0,-2) & (2,0)?

Answer 13

ok, thank-you

Answer 14

and, what about x and b?

Answer 15

Well...you count between the points to determine the slope or m.Look at the graph...there is a point at (0,-2) and another point at (2,0) That's up 2 and right 2. The slope is 2/2 or 1

Answer 16

So on the line with a positive slope, the equation is y = x-2.

Answer 17

\(\bf \begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
&(0\quad ,&-2)\quad &(2\quad ,&0)
\end{array}
\\\quad \\

slope = m= \cfrac{rise}{run} \implies \cfrac{y_2-y_1}{x_2-x_1}
\\ \quad \\

y-y_1=m(x-x_1)\qquad\textit{plug in your values and solve for "y"} \)

Answer 18

On the other line with a negative slope you have a point at (0,3) and (-2,7). Do you see it. Count and figure out the slope

Answer 19

and you do the same for the other line, find 2 points, get the slope, plug in the values in the "point-slope form" and solve for "y"

Answer 20

oh and thank-you everybody :)

Answer 21

wait actually, after i did all of that, I got
y< (or equal to)x-2 and
y> (or equal to)-2x+3
Does anyone know what to do after that?