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Mathematics 22 Online
OpenStudy (anonymous):

Find the equation of the normal line to the curve at x= -2 if f(x)= x^3

OpenStudy (mertsj):

1. The normal is the perpendicular. 2. Find the first derivative. 3. Replace x in the first derivative with -2. 4. That is the slope of the tangent. 5. Take the reciprocal of the answer to # 4 and change it to its opposite. 6. That is the slope of the normal. 7. (-2,-8) is a point on y = x^3 8. Find the equation of a line whose slope is the answer to #5 and contains the point (-2,-8)

OpenStudy (anonymous):

How do I "Find the first derivative"

OpenStudy (mertsj):

You learn that in calculus. Have you had calculus or pre-calc?

OpenStudy (anonymous):

im in calculus right now

OpenStudy (mertsj):

At the end of the first semester, right?

OpenStudy (anonymous):

yes

OpenStudy (mertsj):

y'=3x^2

OpenStudy (anonymous):

oh okay i understand the power becomes the constant and the power is subtracted by one. thank you!!

OpenStudy (mertsj):

yw

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