Find the equation of the normal line to the curve at x= -2 if f(x)= x^3
1. The normal is the perpendicular. 2. Find the first derivative. 3. Replace x in the first derivative with -2. 4. That is the slope of the tangent. 5. Take the reciprocal of the answer to # 4 and change it to its opposite. 6. That is the slope of the normal. 7. (-2,-8) is a point on y = x^3 8. Find the equation of a line whose slope is the answer to #5 and contains the point (-2,-8)
How do I "Find the first derivative"
You learn that in calculus. Have you had calculus or pre-calc?
im in calculus right now
At the end of the first semester, right?
yes
y'=3x^2
oh okay i understand the power becomes the constant and the power is subtracted by one. thank you!!
yw
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