Adult panda weights are normally distributed with a mean of 200 pounds and a standard distribution of 20 pounds. The largest pandas weigh over 250 pounds. Approximately what percent of the adult pandas weight over 250 pounds?
where do I start...
same story, z = (value - mean)/(standard deviation) = (250-200)/20 and look up.
I understand that but that equals a positive 2.5... @douglaswinslowcooper
@douglaswinslowcooper Wait would it be 62.1%? (250-200)/20 = 2.5 p(z>2.5)=1 p(z<2.5)=.621 1-.621= .379 100-37.9= 62.1
You want fraction greater than 250, which is P(z>2.5), which is (look exact value up) less than 1%.
That is .621% @douglaswinslowcooper
Jordi: what you've calculated (2.5) is a z-score. Suggest labeling it as such: z=2.5. Douglas wants you to look up this z score in a Standard Normal Distribution table. Have one? If so, look up z=2.5 on the left edge and determine from the table what the area to the left of that is.
Yes, good work. 0.62% is correct.
Nice work, Jordi, so long as you understand why you're using z=-2.5 when the z score you calculated was z=+2.5.
@mathmale @douglaswinslowcooper
The answer choices are completly different
You are looking at the tail, P(z>=2.5), which has the same probability as the other tail, P(z<=-2.5) for the normal distribution.
So am I right? @douglaswinslowcooper
I think you and I are right. What are your choices?
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