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Mathematics 21 Online
OpenStudy (anonymous):

Tushar a motorist uses 24% of his fuel in covering the first 20% of his total journey (in city driving conditions). If he knows that he has to cover another 25% of his total journey in city driving conditions, what should be the minimum percentage increase in the fuel efficiency for non-city driving over the city driving fuel efficiency, so that he is just able to cover his entire journey without having to refuel? (Approximately)

OpenStudy (anonymous):

This is pretty difficult for me, I will give it a go though: The method that I would use is ratios. We can say that 24% of fuel is equivalent to 20% of driving: Therefore: 24:20 and there is 45% of city driving in total so alter the ratio accordingly: 24:20 54:45 (multiply both sides by 2.25) Therefore he will use 54% of his fuel after 45% of the journey. By using this we can say that he has 46% of his fuel left for 55% of his journey. Fuel efficiency is generally measured in distance traveled divided by the amount of fuel used. We can use this to calculate the efficiency for the city driving: 45%/54% = 0.833% of distance per 1% of fuel. In order for the journey to be possible, he must use the amount of fuel left to travel the distance left so: 55%/46% = 1.196% of distance per 1% of fuel We can now compare the two efficiencies. The question asks for non-city over city so: 1.196/0.833 = 1.436 which is 144% in a percentage. So the increase in efficiency would have to be 144%.

OpenStudy (anonymous):

43.6 efficiency.becoz 100-143.6=43.6%

OpenStudy (anonymous):

Yeah, there are a few ways of expressing it. I just like leaving that 100% on there because it's correct in a fractional sense.

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