Question

Use these points to write the equation of the parabola in standard form (3,0) (-4,-5) (4,-5)

Answer 1

say the required parabola eq'n is : \(a(x-h)^2 + k\)

Answer 2

it goes thru two symmetrical points about y-axis : (-4,-5) and (4,-5)
that means, x-coordinate of its vertex is 0
h = 0

Answer 3

Yeah that's what I got I was trying to make sure thank you

Answer 4

find other values a and k, by plugging in any two points

Answer 5

\(a(x-0)^2 + k\)

plugin (3, 0) above
0 = a(3)^2 + k
0 = 9a + k --------(1)

plugin (4,-5) above
-5 = a(4)^2+k
-5 = 16a + k --------(2)


solving both,
a = -5/7
k = 45/7

Answer 6

so the required parabola wud be :-
\(\frac{-5}{7}(x-0)^2 + \frac{45}{7}\)

Answer 7

Yay! I was right thank you

Answer 8

np... u wlc :)

Answer 9

Another question, sorry for being a bother for Vertex form I use the equation of f(x)=ax^2+bx+c right?

Answer 10

thats standard form !

Answer 11

standard form : f(x) = ax^2+bx+c
vertex form : f(x) = a(x-h)^2+k