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OpenStudy (anonymous):

a road has a hump of 2.5m. what is the minimum speed at which a car will leave the road at the top of the hump

OpenStudy (anonymous):

the kinetic energy is 1/2mv^2 and the gravitational potential energy is mgh. hence u will get an equation according to the conservation law of mechanic energy. 1/2mv^2=mgh, so v(min)=(gh)^.5=50^.5=2.24

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