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Mathematics 17 Online
OpenStudy (anonymous):

gyifgngun

OpenStudy (anonymous):

Commutative Property is when you can change the order of the numbers involved without changing the result. Addition and multiplication are both commutative, while subtraction is not. The Inverse Property of Multiplication states that the product of any number and its multiplicative inverse is 1. An operation is associative if you can group numbers in any way without changing the answer. It doesn't matter how you combine them, the answer will always be the same. Addition and multiplication are both associative. Therefore, the property of the equation you provided is associative.

OpenStudy (anonymous):

This is the associative property of addition. Commutativity is where: \[a+b=b+a\] Whereas associativity is where: \[(a+b)+c = a+(b+c)\]

OpenStudy (anonymous):

I'll try my best

OpenStudy (anonymous):

1/5 is rational by definition. A rational number is one that can be expressed in the form a/b, where a and b are both integers and b is not 0.

OpenStudy (anonymous):

Well whole numbers are like (1, 2, 3, .....) so we'll cancel the 3rd and 4th choice

OpenStudy (anonymous):

Note that a number being rational also implies that it is real and algebraic.

OpenStudy (anonymous):

So yes @Indivicivet is right

OpenStudy (anonymous):

Yes and rational numbers are also those that either have a terminating or repeating decimal.

OpenStudy (anonymous):

Rational is the correct answer.

OpenStudy (anonymous):

Sure

OpenStudy (anonymous):

7(p+5)

OpenStudy (anonymous):

5(p+7)

OpenStudy (anonymous):

@Indivicivet are you sure?

OpenStudy (anonymous):

"the product of [5 more than p] and [7]" => "[5 more than p] * [7]" It could only be interpreted otherwise as "the product of [5 more than [p and 7]]" which doesn't make any sense, even if you could evaluate "p and 7" (because the implied product operator would be mismatched): \[((p \cup 7)+5)*\]

OpenStudy (anonymous):

Oh ok.

OpenStudy (anonymous):

@Indivicivet Gotcha

OpenStudy (anonymous):

is the question radical 1 divided by 121. (121 outside of the radical) its not clear

OpenStudy (anonymous):

Well i considered it to be radical 1 divided by 121. (121 included in the radical) then it's B since 1 is divisible by itself and 121 is 11*11

OpenStudy (anonymous):

I think it's safe to assume the question asks for the simplest form of \[\sqrt{\frac{1}{121}}\] which follows easily from knowing that: \[\sqrt{\frac{a}{b}} = \frac{\sqrt{a}}{\sqrt{b}}\]

OpenStudy (anonymous):

If it's radical one divided by 121 (121 is outside the radical then it's 1/121 which wasn't a choice. @Indivicivet explained it nicely

OpenStudy (anonymous):

Well like @Indivicivet said when you have a fraction under one big radical then break it down a bit and give the numerator its own radical and the denominator its own radical. Then you do the square root for each one separately whilst both are still fractions.

OpenStudy (anonymous):

radical 1 is 1. radical 121 is 11 because 11*11 is 121. So the overall answer is 1/121.

OpenStudy (anonymous):

Well it's B. But ill give you a different example to make it clearer

OpenStudy (anonymous):

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