Question

How many solutions are there to the following system of equations?

2x + 6y = –12
10x + 32y = –62

A.
infinitely many

B.
0

C.
1

D.
2

Answer 1

By looking at the two equations, you can tell they are not one single line, and they are not parallel lines. Automatically, that means they are two intersecting lines. That means 1 solution.

Answer 2

first, lets reduce the equations..

2x + 6y = -12 reduces to x + 3y = -6

10x + 32y = -62 reduces to 5x + 12y = - 31

so we have :
x + 3y = -6 --->(-5)
5x + 12y = -31
------------
-5x - 15y = 30 (result of multiplying by -5)
5x + 12y = -31
-------------add
-3y = -1
y = 1/3

I am not going to figure x, because I do not need to.

There is going to be 1 solution

Answer 3

thank you!

Answer 4

x=-3 y=-1

Answer 5

(2x+6y=-12)10
(10x+32y=-62)2
20x+60y=-120
(-)20x+64y=-124
-20x-64y=+124
-4y=4
y=-1
2x+6(-1)=-12
2x-6=-12
x=-12+6/2
x=-3
check x=-3 y=-1 in equation 2
10(-3)+32(-1)=-62
-62=-62

Answer 6

please medal